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School-trip buses: subtract, then divide equally

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    Solution steps

      Word problems · Equal groups

      Question

      A school has 808 students travelling on six buses. The first bus has already taken 128 students. The other five buses carry equal numbers of students. How many students are on the last bus?

      Bar model for assigning students to busesOf 808 students, 128 take the first bus. The remaining 680 share five buses, with 136 students each.Total: 808 studentsBus 1: 128Other 5 buses: 808 − 128 = 680Bus 2: 136Bus 3: 136Bus 4: 136Bus 5: 136Last: 136Each bus: 680 ÷ 5 = 136 students
      Subtract 128 from 808, then divide the remaining 680 students equally among five buses.

      Step-by-step solution

      1. Identify the total and the groups

      There are 808 students and six buses. The first bus has 128 students. The last bus is one of the other five equal groups.

      2. Find how many students remain

      Subtract those already on the first bus: 808 − 128 = 680 students.

      3. Divide the remainder equally

      The remaining 680 students share five buses: 680 ÷ 5 = 136 students per bus.

      4. Answer the question

      Each of the other five buses carries 136 students, so the last bus also carries 136 students.

      The last bus carries 136 students.

      Which method does this problem use?

      First subtract to find the quantity to be shared. Then divide by the number of equal groups. A bar model helps connect each operation to the quantity it represents.